Pseudo sunflowers

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Abstract

A collection A0,A1,,At of finite sets is called a pseudo sunflower of size t+1 and with center C if C is a proper subset of A0 and the sets A0C,,AtC are pairwise disjoint. The main result shows that every collection of more than tk distinct k-element sets contains a pseudo sunflower of size t+1. The bound is best possible.

Introduction

Let k and t be positive integers. A collection of distinct k-element sets or k-sets for short, is called a k-uniform family or for short a k-graph.

A sunflower (of size t+1 and with center C ) is a collection of t+1 distinct sets A0,,At such that AiAj=C for all 0i<jt.

Let us recall a simple but very important result due to Erdős and Rado. We need a definition. Let s(k,t) denote the maximum of |F| where F is a k-graph not containing any sunflower of size t+1. Note that s(k,1)=1 and s(1,t)=t are trivial.

Erdős–Rado Sunflower Lemma ([1]). s(k,t)k!tk.

The proof is by simple induction but this result played an essential role in the proof of many combinatorial results (cf. e.g. [2]) and also in the seminal paper of Razborov [3] concerning complexity theory. Most applications are based on the following simple fact.

Deza’s Lemma (cf. [2]). Suppose that A0,,At form a sunflower with center C, and B is a set of size at most t. Then BAi=BCholdsforsomei,0it.

The term sunflower was coined in [4]. Abbott et al. [5] determined s(2,t). For t=2, even one has s(2,2)=2(2+1) the lower bound coming from the vertex disjoint union of two complete graphs on 2+1 vertices.

The inequality s(k+,t)s(k,t)s(,t) is easy to prove. It implies that either s(k,t)<c(t)k for some c(t) independent of k or s(k,t)1/k.

Mentioning (1.3) was a constant subject in Erdős’s many papers including a list of his favorite problems [6].

Even though that there was some major progress throughout the years (cf. [7], [8]), (1.3) is still open even for t=2.

Let us recall that a family F of sets is called r-intersecting if |FF|r for all F,FF. The author has been using the Erdős–Rado Sunflower Lemma since a long time ([9], [10], etc.).

However it turns out that in many problems concerning r-intersecting families BAiBC would be sufficient instead of (1.2). This motivates the following definition.

Definition 1.1

The sets A0,,At are said to form a pseudo sunflower of size t+1 and center C if CA0 and the sets A0C,A1C,,AtC are pairwise disjoint.

We should point out that for any set D with CDA0 the sets A0,,At form a pseudo sunflower with center D as well.

Instead of Deza’s Lemma we have the following.

Lemma 1.2

Suppose that A0,,At form a pseudo sunflower with center C and B is a set of size at most t. Then BAiBC holds for some i,0it.

Proof

Since |B|t and A0C,,AtC are t+1 pairwise disjoint sets, B(AiC)= must hold for some i, 0it. This is equivalent to (1.4). 

Definition 1.3

Let p(k,t) denote the maximum of |F| over all k-graphs F not containing a pseudo sunflower of size t+1.

Example 1.4

Let X1,,Xk be pairwise disjoint t-sets and let K=K(X1,,Xt)={E:|E|=k,|EXj|=1 for 1jk}.Clearly, |K|=tk.

Claim 1.5

K does not contain a pseudo sunflower of size t+1.

Proof

Suppose for contradiction that E0,,EtK form a pseudo sunflower with center C. Then CE0 implies |C|<k. Thus we may choose j to satisfy CXj=. Then |(EiC)Xj|=1 for 0it. Since |Xj|=t, they cannot be pairwise disjoint. 

Rather surprisingly and in great contrast to sunflowers we can prove that p(k,t)=tk and Example 1.4 is the essentially unique k-graph attaining equality.

Let us state our main result in a sharper form.

Theorem 1.6

Let t,k,r be positive integers and let F be a k-graph not containing any pseudo sunflower of size t+1. Then |F|tk.Moreover, the inequality is strict unless F is isomorphic to K. If in addition F is r-intersecting, then |F|tk0j<rkj(t1)kj.

For the proof we use the following standard notation. Let F be a family of sets and D,E subsets with DE. Set F(D,E)={FD:FF,FE=D}.Note that for E fixed |F|=DE|F(D,E)|and if EF and F is r-intersecting, then |F|=DE,|D|r|F(D,E)|.

In Section 2 we provide the proof of Theorem 1.6. In Section 3 some applications are given.

Section snippets

The proof of Theorem 1.6

Using p(k,1)=1 and p(1,t)=t we prove (1.5) by induction. The induction step is based on the following lemma, t2.

Lemma 2.1

Suppose that F contains no pseudo-sunflower of size t+1. Then for all EF and DE, the family F(D,E) contains no pseudo-sunflower of size t.

Proof of the lemma

Assume for contradiction that B0,,Bt1F(D,E) span a pseudo sunflower with center CB0. Set |D|=. If =k then F(D,E)={}, i.e., |F(D,E)|<t and we are done. For 0<k define Ai=BiD, 0i<t and note AiF. Set At=E and C˜=CD. By definition AiAt=

Applications

For a finite set X and a k-graph FXk and an integer r, 1r<k define the family of r-covers R(F,r) by R(F,r)={RX,|RF|r for each FF}.With this definition F is r-intersecting iff FR(F,r). Let us define P(F,r) as the family of minimal sets in R(F,r): P(F,r)={PR(F,r):RR(F,r),RP}.

Proposition 3.1

There is no pseudo-sunflower of size kr+2 in P(F,r).

Proof

Suppose for contradiction that P0,,Pkr+1P(F,r) form a pseudo sunflower with center CP0. By definition CP(F,r). Consequently, for some FF, |FC|=r for

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