Abstract
If we want to apply Galvin’s kernel method to show that a graph G satisfies a certain coloring property, we have to find an appropriate orientation of G. This motivated us to investigate the complexity of the following orientation problem. The input is a graph G and two vertex functions \({f, g : V(G) \to \mathbb{N}}\). Then the question is whether there exists an orientation D of G such that each vertex \({v \in V(G)}\) satisfies \({\sum_{u \in N_D^{+}(v)}g(u) \leq f(v)}\). On one hand, this problem can be solved in polynomial time if g(v) = 1 for every vertex \({v \in V(G)}\). On the other hand, as proved in this paper, the problem is NP-complete even if we restrict it to graphs which are bipartite, planar and of maximum degree at most 3 and to functions f, g where the permitted values are 1 and 2, only. We also show that the analogous problem, where we replace g by an edge function \({h : E(G) \to \mathbb{N}}\) and where we ask for an orientation D such that each vertex \({v \in V(G)}\) satisfies \({\sum_{e \in E_D^{+}(v)}h(e) \leq f(v)}\), is NP-complete, too. Furthermore, we prove some new results related to the (f, g)-choosability problem, or in our terminology, to the list-coloring problem of weighted graphs. In particular, we use Galvin’s theorem to prove a generalization of Brooks’s theorem for weighted graphs. We show that if a connected graph G has a block which is neither a complete graph nor an odd cycle, then G has a kernel perfect super-orientation D such that \({d_{D}^{+}(v) \leq d_G(v)-1}\) for every vertex \({v \in V(G)}\).
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Research supported in part by the DAAD and by the Hungarian Scientific Research Fund, grant OTKA T-81493.
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Stiebitz, M., Tuza, Z. & Voigt, M. Orientations of Graphs with Prescribed Weighted Out-Degrees. Graphs and Combinatorics 31, 265–280 (2015). https://doi.org/10.1007/s00373-013-1382-0
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DOI: https://doi.org/10.1007/s00373-013-1382-0